Write a C Program to Find the Sum of All the Positive and Negative Numbers in Array

Statement of C Program: This Program reads N integers (+ve , -ve and zero) into an Array A and Finds

1. The sum of positive numbers
2. The sum of negative numbers
3. The average of all input numbers.

#include<stdio.h>

#include<conio.h>

#define MAX 8

void main()

{

int Array[MAX] ;

int i , N ;

int negsum , posum;    
/* negsum stands for Sum of Negative Numbers and posum stands for Sum of Positive Numbers */

float total , average;

clrscr();

negsum = 0 ;

posum = 0;

total = 0;

printf(" Enter the value of N\n");

scanf("%d" , &N);

printf(" Enter %d numbers( -ve , +ve and 0 )\n" , N);

for(i=0 ; i<N ; i++)

{

scanf(" %d" , &Array[i] );

}

printf(" Array elements\n");

for(i=0 ; i<N ; i++)

{

printf("%d\n" , Array[i] );

}

for(i=0 ; i<N ; i++)

{

if(Array[i] < 0)

{

negsum + = Array[i];

}

else if(Array[i] > 0)

{

posum + = Array[i] ;

}

else if(Array[i] == 0)

{

       ;

}

total + = Array[i];

}

average = total / N;

printf(" Sum of all positive numbers =%d\n" , posum);

printf(" Sum of all negative numbers =%d\n" , negsum);

printf(" Average of all input numbers %f\n" , average);

}                                                  / * End of main() */

 Output:

 Enter the value of N

  5

 Enter 5 numbers (-ve , +ve and 0)

  6

 -7

  0

 -3

  5

 Array elements

  6

 -7

  0

 -3

  5

 Sum of all positive numbers = +11

 Sum of all negative numbers = -10

 Average of all input numbers = 0.20

                                                                   That's All